SOLUTION: Please help with this problem and its graph. x-3/x+5 < 0 Thanks, Marcus

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Question 23316: Please help with this problem and its graph.
x-3/x+5 < 0
Thanks,
Marcus

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Solving inequalities can most easily be solved by graphing calculator methods.

First of all, did you mean %28x-3%29%2F%28x%2B5%29+%3C0+ or did you mean x-%283%2Fx%29%2B5%3C0? I think you probably meant the first. I will solve this one, and if I have misinterpreted your problem, then either let me know by Email or re-post the problem and we'll give it another try.

+%28x-3%29%2F%28x%2B5%29%3C0

The first step is to graph +y=+%28x-3%29%2F%28x%2B5%29+. Because the problem says <0, you need to find all values of x for which the graph is BELOW THE X-AXIS! If the problem had been +%28x-3%29%2F%28x%2B5%29%3E0, then you would draw the same graph, but to solve this one, you need to find all values of x where the graph of +y=+%28x-3%29%2F%28x%2B5%29+ is ABOVE THE Y-AXIS!

So here is the graph:
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C+%28x-3%29%2F%28x%2B5%29+%29+
Notice that the graph crosses the x-axis at x= 3. Notice that it looks like a vertical line at x=-5. This is actually an ASYMPTOTE, which SHOULD be drawn with a DOTTED LINE. An asymptote is a value of x where the graph will go off to infinity--it never quite gets to that value of x, which in this case is at x= -5. Notice that this graph is BELOW THE X-AXIS from -5 to 3, so the answer is -5%3Cx%3C3. Interval notation for this problem will be (-5,3).

This may not have been what you were expecting in a problem. I think it's MUCH easier than the old ways that I used to teach.

R^2 at SCC