SOLUTION: what are the roots if in ractored form it is y=(2x-3)(3x+4)? what is the axis of symmetry?

>>what are the roots if in factored form it is y=(2x-3)(3x+4)?<<

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The "roots" are found by replacing y by 0 and solving for x

y = (2x-3)(3x+4)

0 = (2x-3)(3x+4)

set each parenthetical factor = 0

2x-3=0, or x = 3/2

3x+4=0, or x = -4/3

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what is the axis of symmetry?

The equation of the axis of symmetry is

x = (the average of the two roots)

or rather:

x = (r1 + r2)/2

x = [(3/2) + (-4/3)]/2 

x = (3/2 - 4/3)/2

x = (9/6 - 8/6)/2

x = (1/6)/2

x = 1/12

That's its equation, x = 1/12

Edwin