You can put this solution on YOUR website! Find two consecutive even integers whose product is 48.
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The quick and easy way:
sqrt(48) is ~7 (7*7=49).
It's the numbers above and below 7,
6 and 8 (and -8 and -6)
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The hard way:
n*(n+2) = 48
n^2 + 2n - 48 = 0
(n+8)*(n-6) = 0
--> 6 & 8 and -8 & -6
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and
Find two consecutive odd integers whose product is 63.
Do this one the same way.