SOLUTION: How do you solve: x-6sqrtx+8=0 and (x^2-6x)^2-22(x^2-6x)-135=0

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Question 211200: How do you solve: x-6sqrtx+8=0
and
(x^2-6x)^2-22(x^2-6x)-135=0
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x-6sqrt(x)+8=0
x+8=6sqrt(x)
x^2+16x+64=36x square each side.
x^2-20x+64=0
(x-16)(x-4)=0
x=16, x=4
.
Ed