SOLUTION: I have no idea how to solve this. I am probably making it harder then it is. Can someone please help me? Trains A and B are traveling in the same direction on parallel tracks.

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Question 209651: I have no idea how to solve this. I am probably making it harder then it is. Can someone please help me?
Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 12.25 P.M. If train B passes the same station at 12:37, at what time will train B catch up to train A? ______?

Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
D=RT
THE DISTANCES WILL BE THE SAME. THEREFORE:
Da=100T
Db=125(T-.2)
100T=125(T-.2)
100T=125T-25
100T-125T=-25
25T=-25
T=-25/-25
T=1 HOUR IS THE TIME FOR TRAIN b TO CATHCH TRAIN a.
PROOF:
100*1=125(1-.2)
100=125*.8
100=100

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 100 miles per hour and train B is traveling at 125 miles per hour.
Train A passes a station at 12.25 P.M. If train B passes the same station at 12:37,
at what time will train B catch up to train A? ______?
:
from the given information, we know that train B is 12 min (.2 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: .2 * 125 = 25 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 25 mi
125t = 100t + 25
125t - 100t = 25
t =
t = 1 hr
:
12:25 + 1 = 1:25 pm, B catches A
:
:
Check solution by finding the distances (train B travels 25 mi more than train A)
125 * 1 = 125 mi
100 * 1 = 100 mi
-------------------
difference = 25 mi