Question 20906: I have been asked to solve the equations simultaneously, and i believe one of them to be a quadratic equation, and so am stuck - please can you help me?
x-y=3
2
x -10y-6=0
P.s. If you could show me how to achieve the answer, possibly it would help me understand it?
Thankyou so much.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! x-y=3
x=y+3...or...y=x-3....
x^2 -10y-6=0 ,substituting y=x-3 from above eqn. in this we get ,
x^2-10(x-3)-6=0
x^2-10x+30-6=0
x^2-10x+24=0
find 2 factors for 24 which add up to -10.we find that -6*-4=+24 and -6-4=-10...so
x^2-6x-4x+24=0
x(x-6)-4(x-6)=0
(x-6)(x-4)=0
x-6=0 ....or...x-4=0
x=6...or...x=4
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