SOLUTION: two consecutive odd integers whose product is 323

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Question 207435: two consecutive odd integers whose product is 323
Found 2 solutions by rfer, Alan3354:
Answer by rfer(16322) About Me  (Show Source):
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
two consecutive odd integers whose product is 323
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Do you prefer the hard way which takes longer? Or the easy way?
The hard way:
x*(x+2) = 323
x^2 + 2x - 323 = 0
If you spot that it can be factored:
(x+19)*(x-17) = 0
x = -19 --> -19 & -17
x = 17 ---> 17 & 19
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The easy way:
sqrt(323) is almost 18.
The numbers are adjacent to 18, 17 & 19.