Question 207261: question is: solve the quadratic equation by completing the square:
x^2+6x=0
x^2+6x(6/2)^2 = (6/2)^2
(sqrt x + sqrt 3^2)^2 = sqrt 9
x+3= +- 3
x+3=3 x+3=-3
x=0 x=-6
This question is not from a textbook, I would like to know if I did the work correctly, thank you so much for your help.
Found 2 solutions by RAY100, solver91311:
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! x^2 +6x =0
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complete square by using (6/2)^2 as 3rd term,,,however must add to both sides to maintain balance.
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x^2 +6x +(6/2)^2 = (6/2)^2
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x^2 +6x +9 = 9
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(x+3)^2 = 9
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take square root of both sides
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+/-(x+3) = +/-(3)
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+ x+3 =+3,,,x=0,,,,check,,(0)^2 +6(0)=0,,,ok
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-x-3 = -3,,,x=0,,,check,,ok
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x+3=-3,,,x=-6,,check (-6)^2 +6(-6)=0,,,36-36=0,,,ok
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-x-3=+3,,,,x=-6,,,,check,,,ok
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Therefore,,,x=0,-6
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Answer by solver91311(24713)  (Show Source):
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