SOLUTION: Hi, I really need help on this one problem... I need to solve for "x" by taking the square root, and there should be two answers. {{{2x^2 = 100}}} I just don't understand how to d

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hi, I really need help on this one problem... I need to solve for "x" by taking the square root, and there should be two answers. {{{2x^2 = 100}}} I just don't understand how to d      Log On


   

Question 206189: Hi, I really need help on this one problem... I need to solve for "x" by taking the square root, and there should be two answers. 2x%5E2+=+100
I just don't understand how to do it... if you could show me, I would be deeply grateful.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2=100 Start with the given equation.


x%5E2=%28100%29%2F%282%29 Divide both sides by 2.


x%5E2=50 Reduce.


x=%22%22%2B-sqrt%2850%29 Take the square root of both sides.


x=sqrt%2850%29 or x=-sqrt%2850%29 Break up the "plus/minus" to form two equations.


x=5%2Asqrt%282%29 or x=-5%2Asqrt%282%29 Simplify the square root.


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Answer:


So the solutions are x=5%2Asqrt%282%29 or x=-5%2Asqrt%282%29.