SOLUTION: hi can you plzz help me with this question...thanks!
The path of a basketball shot can be modeled by the equation h = -0.09dē + 0.9d + 2 where h is the height of the basketball, i
Question 204443: hi can you plzz help me with this question...thanks!
The path of a basketball shot can be modeled by the equation h = -0.09dē + 0.9d + 2 where h is the height of the basketball, in metres, and d is the horizontal distance of the ball from the player, in metres.
a) What is the maximum height reached by the ball?
b) What is the horizontal distance of the ball from the player when it reaches its maximum height?
c) How far from the floor is the ball when the player releases it?
You can put this solution on YOUR website! Starting with:
a) The maximum h can be found at the vertex of the parabola at: Now substitute this value of d into the given equation and solve for h.
The maximum height is 4.25 metres.
b) The distance d when the ball has reached a height of 4.25 metres is: Subtract 4.25 from both sides. Solve using the quadratic formula: where: a = -0.09, b = 0.9, and c = 2.25 and instead of x in the formula, we want to use d, so... metres.
c) From the original equation, the ball is 2 metres from the floor when the player releases it.
The general form of the equation for the height (h) an object propelled upward with an initial velocity from an initial height of is: and = 2.
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