SOLUTION: please help me solve the following problem f(x)= x^2-4x+3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: please help me solve the following problem f(x)= x^2-4x+3      Log On


   



Question 202085: please help me solve the following problem f(x)= x^2-4x+3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Notice that the quadratic x%5E2-4x%2B3 is in the form of Ax%5E2%2BBx%2BC where A=1, B=-4, and C=3


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-4%29+%2B-+sqrt%28+%28-4%29%5E2-4%281%29%283%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-4, and C=3


x+=+%284+%2B-+sqrt%28+%28-4%29%5E2-4%281%29%283%29+%29%29%2F%282%281%29%29 Negate -4 to get 4.


x+=+%284+%2B-+sqrt%28+16-4%281%29%283%29+%29%29%2F%282%281%29%29 Square -4 to get 16.


x+=+%284+%2B-+sqrt%28+16-12+%29%29%2F%282%281%29%29 Multiply 4%281%29%283%29 to get 12


x+=+%284+%2B-+sqrt%28+4+%29%29%2F%282%281%29%29 Subtract 12 from 16 to get 4


x+=+%284+%2B-+sqrt%28+4+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%284+%2B-+2%29%2F%282%29 Take the square root of 4 to get 2.


x+=+%284+%2B+2%29%2F%282%29 or x+=+%284+-+2%29%2F%282%29 Break up the expression.


x+=+%286%29%2F%282%29 or x+=++%282%29%2F%282%29 Combine like terms.


x+=+3 or x+=+1 Simplify.


So the solutions are x+=+3 or x+=+1