SOLUTION: Please help. I'm not sure I have this done correctly. 3/-5-x - x/x-3=0

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Question 201334: Please help. I'm not sure I have this done correctly.
3/-5-x - x/x-3=0

Found 2 solutions by RAY100, MathTherapy:
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Please review to assure correct problem
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3/(-5-x) - x/(x-3)
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just rearrange the first term, to get better den
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-3/(x+5) -x /(x-3)
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LCD = (x+5)(x-3)
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[ -3 (x-3) -x(x+5)] / (x+5)(x-3)
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[ -3x +9 -x^2 -5x ] / (x+5)(x-3)
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[ -x^2 -8x +9 ] / (x+5)(x-3)
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[ -1 ( x^2 +8x -9) ] / ( x+5)(x-3)
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[-1 (x-1)(x+9)] / [ (x+5)(x-3) ]
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checking let x=0 in original and answer,,,both = -3/5,,,,ok
doing same for x=1, both = zero,,,ok

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
3%2F%28-5-x%29-x%2F%28x-3%29+=+0
Multiply equation by LCD (-5-x)(x-3). This gives us:
3(x-3) – x(-5-x) = 0(-5-x)(x-3) = 3x-9%2B5x%2Bx%5E2+=+0

3x-9%2B5x%2Bx%5E2+=+0 = x%5E2+%2B+8x+-+9+=+0
(x + 9)(x – 1) = 0

Therefore, x = - 9 or 1, or {- 9, 1}.

Checking, when x = - 9
3%2F%28-5-x%29-x%2F%28x-3%29+=+0 = 3%2F%28-5-%28-9%29%29--9%2F%28-9-3%29+=+0


3%2F%28-5%2B9%29%2B9%2F%28-12%29+=+0 = 3%2F4%2B9%2F%28-12%29+=+0

Multiply equation by LCD, - 12
-3(3) + 1(9), or, -9 + 9 = 0 (TRUE)

Checking, when x = 1
3%2F%28-5-x%29-x%2F%28x-3%29+=+0 = 3%2F%28-5-1%29-1%2F%281-3%29+=+0

3%2F%28-5-1%29-1%2F%281-3%29+=+0 = 3%2F-6-1%2F-2+=+0

Multiply equation by LCD, - 6
1(3) – 3(1) = 0, or, 3 – 3 = 0 (TRUE)