SOLUTION: Can you please help me solve this equation. {{{x^2-2x-13=0}}}
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Question 200198
This question is from textbook
Mathematics in Our World
:
Can you please help me solve this equation.
This question is from textbook
Mathematics in Our World
Found 2 solutions by
jim_thompson5910, checkley77
:
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Start with the given equation.
Notice that the quadratic
is in the form of
where
,
, and
Let's use the quadratic formula to solve for "x":
Start with the quadratic formula
Plug in
,
, and
Negate
to get
.
Square
to get
.
Multiply
to get
Rewrite
as
Add
to
to get
Multiply
and
to get
.
Simplify the square root (note: If you need help with simplifying square roots, check out this
solver
)
Break up the fraction.
Reduce.
or
Break up the expression.
So the solutions are
or
which approximate to
or
Answer by
checkley77(12844)
(
Show Source
):
You can
put this solution on YOUR website!
x^2-2x-13=0
Using the quadratic equation:
We get:
x=(2+-sqrt[-2^2-4*1*-13])/2*1
x=(2+-sqrt[4+52)/2
x=(2+-sqrt56)/2
x=(2+-7.48)/2
x=(2+7.48)/2
x=9.48/2
x=4.74 ans.
x=(2-9.48)/2
x=-7.48/2
x=-3/74 ans.