SOLUTION: The width of a rectangle is 1 ft less than the length. The area is 2ft squared. Find the width and lenght.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The width of a rectangle is 1 ft less than the length. The area is 2ft squared. Find the width and lenght.      Log On


   

Question 199938: The width of a rectangle is 1 ft less than the length. The area is 2ft squared. Find the width and lenght.
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Area =Length * Width = 2 ft^2
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but w = L-1
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L * ( L-1) = 2
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L^2 -L -2 = 0
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( L -2) (L+1) =0
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L-2 =0,,,,L=2,,,,and w=L-1 = 1,,,ok
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or L+1 =0,,,,,L=-1,,,,which is not reasonable
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check
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Area = L*W = 2*1 =2 ,,,,ok