SOLUTION: Can you please help me to solve this equation (x+10)(2x-3)=54? I dont know how to solve it using quadratic equations. Thank you very much!!!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Can you please help me to solve this equation (x+10)(2x-3)=54? I dont know how to solve it using quadratic equations. Thank you very much!!!      Log On


   

Question 197851: Can you please help me to solve this equation (x+10)(2x-3)=54? I dont know how to solve it using quadratic equations. Thank you very much!!!
Found 3 solutions by checkley77, Mathtut, stanbon:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
(x+10)(2x-3)=54
2x^2+20x-3x-30=54
2x^2+17x-30-54=0
2x^2+17x-84=0
(2x-7)(x+12)=0
2x-7=0
2x=7
x=7/2
x=3.5 ans.
x+12=0
x=-12 ans.













Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B10%29%282x-3%29=54
:
2x%5E2-3x%2B20x-30=54 multiplied terms
:
2x%5E2%2B17x-84=0 gathered like terms into quadratic form
:
2x-7%29%28x%2B12%29 factored
:
x=7/2 and x=-12

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve this equation (x+10)(2x-3)=54
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2x^2 -3x+20x -30 = 54
2x^2 + 17x -74 = 0
x = [-17 +-sqrt(17^2-4*2*-74)]/4
x = [-17 +- 31]/4
x = 7/2 or x = -12
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Cheers,
Stan H.