SOLUTION: Hello, I have to provide a real life example of quadratic function. I have no idea where to start. Can you help me with some ideas and formulas for the everyday use of quadratic fu

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Question 197245: Hello, I have to provide a real life example of quadratic function. I have no idea where to start. Can you help me with some ideas and formulas for the everyday use of quadratic function? Thank you.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

A rectangular field adjacent to the straight bank of a river is to 
be fenced, but there is to be no fencing along the riverbank. If 180 m 
of fencing is available, what is the maximum area that can be 
enclosed?

We draw a rectangle for the area, with a dotted line
for the river bank:

 

If we let x ft. be the length of the left and right sides,
the bottom side will be 200 ft - 2x ft.  So we put x on
the two vertical sides and 200-2x on the horizontal side.



Let y = the area of the rectangle.

Use Area+=+%28base%29%28height%29, so we have

y=%28200-2x%29%28x%29

y=x%28200-2x%29

y=200x-2x%5E2

y=-2x%5E2%2B200x  (Note: this is a quadratic equation)

If we draw the graph of that we get:

graph%28400%2C400%2C-10%2C105%2C-200%2C5100%2C200x-2x%5E2%29
   
Since the graph is symmetrical, the highest point
is right in the middle between the two x-intercepts.

So we find the two x-intercepts by setting y=0 and
solving for x:

y=-2x%5E2%2B200x
0=-2x%5E2%2B200x
2x%5E2-200x=0

Factor the left side:

2x%28x-100%29=0

2x=0,  x-100=0
x=0,   x=100

Halfway between those will be
where x = 50

So the two vertical sides will be 50 feet each,
and the base will be 200 - 2x or

200-2x=200-2%2850%29=200-100=100

or 100 feet.  And that maximum area will be

(base)(height) = (100)(50) = 5000 square feet.

Edwin