SOLUTION: To solve percent mixture problems: How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution? my try: Water x

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: To solve percent mixture problems: How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution? my try: Water x       Log On


   

Question 192446This question is from textbook Intermediate Algebra
: To solve percent mixture problems:
How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution?
my try:
Water x 1.00 x
80% 75 .80 75(.80)
50% 75+x .50 .50(75+x)
x+75(80) =50(75+x)
x+6000=3750 + 50x
-49x = -2250
x = -45.91
????
Wrong?
This question is from textbook Intermediate Algebra

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
the amount of antifreeze remains constant
:
.8(5)=.5(5+x)
:
4=2.5+.5x
:
.5x=1.5
:
x=3 quarts