SOLUTION: MAXIMUM HEIGHT. If a soccer ball is kicked straight up with an initial velocity of 32feet per second, then its height above the earth is a function of time given by s(t)=-16t^2 + 3
Question 19236: MAXIMUM HEIGHT. If a soccer ball is kicked straight up with an initial velocity of 32feet per second, then its height above the earth is a function of time given by s(t)=-16t^2 + 32t. Graph this function for 0 less than or equal(symbol) t less than or equal (symbol)2. What is the maximum height reached by this ball? Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! MAXIMUM HEIGHT. If a soccer ball is kicked straight up with an initial velocity of 32feet per second, then its height above the earth is a function of time given by s(t)=-16t^2 + 32t. Graph this function for 0 less than or equal(symbol) t less than or equal (symbol)2. What is the maximum height reached by this ball?
s(t)=-16t^2 + 32t..take different values for t from 0 to 2 as given(Graph this function for 0 less than or equal(symbol) t less than or equal (symbol)2)and find corresponding values for s(t)..foe ex.when t=1 we get s(1)=-16*1*1+32*1=
-16+32=15....etc..tabulate as below and plot the graph taking time on x axis and s(t) on y axis
t..........0.......0.5........1...........1.5.............2
s(t).......0.......12.........16..........36..............0
you will see a graph of this type...
