SOLUTION: Could some one help me understand this problem?
The instructions are to solve the inequality. Find the vertex and intercepts, then graph it:
y = -3x^2 + 6x
Thanks very m
You can put this solution on YOUR website! SEE THE EXAMPLE BELOW AND DO SIMILAR WAY
The instructions are to solve the inequality. Find the vertex and intercepts, then graph it:
y = -x^2 - 3x - 2
y=-(x^2+3x+2)=-(x^2+2x+x+2)=-(x(x+2)+1(x+2))=-(x+1)(x+2)
we first analyse this ..that is what will be its value if x=0,when will y be zero ,when is it positive,when is it -ve,has it got a maximum or minimum etc...
we can give different values for x and find the corresponding values of y to graph it..let us do
let us put x=0....1....2....3....-1....-2....-3....to show you the method
we get.....y=-2...-6...-12..-20...0.....0....-2....etc..now you can plot a graph with this table...you can take more points also and do it..
we refer to y as the function of x given by y=f(x)= -x^2 - 3x - 2."it"refers to function or y or f(x)
we find it has two zeros (that is y=0)at x=-1 and x=-2...
it is +ve when x is between -1 and -2.
it is -ve if x<-2...or if x>-1
its x intercepts are (that is value of x when y is zero )-1 and -2..that is the graph cuts x axis at x=-1 and x=-2
its y intercept is ( that is value of y when x is zero) is -2
its vertex is at the point when y is minimum or maximum..for this we write y as follows
y=-=-
now we reason that being perfect square ..it is always positive.hence its minimum value is zero (when x=-3/2)..then y =1/4
so we call x=0 and y=1/4 as the vertex of the graph.
