SOLUTION: Method of Elimination.
9. Liz works at ballpark selling bottled water. She sells 37 bottles in one shift. The large bottles sell for $5 each and the small bottles sell for $3 each
Question 182776: Method of Elimination.
9. Liz works at ballpark selling bottled water. She sells 37 bottles in one shift. The large bottles sell for $5 each and the small bottles sell for $3 each. At the end of one game, she has taken in $131.
a) How many large bottles did Liz sell?
b) How many small bottles did she sell?
Please and thank you very much Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! 9. Liz works at ballpark selling bottled water. She sells 37 bottles in one shift. The large bottles sell for $5 each and the small bottles sell for $3 each. At the end of one game, she has taken in $131.
a) How many large bottles did Liz sell?
b) How many small bottles did she sell?
:
let call the number of large and small bottles sold L and S, respectively
:
L+S=37...........eq 1
5L+3S=131........eq 2
:
multiply eq 1 by -3 and add the two equations together...
:
-3(L+S=37)=-3L-3S=-111
:
-3L-3S=-111......eq 1 revised
5L+3S=131........eq 2
:
adding equations together, we can see that the S terms are eliminated because
-3S+3S=0. we are left with -3L+5L=-111+131
:
2L=20
:
a)number of Large bottles sold
:
take L's found value and plug it back into any numbered equation. I will use eq2
:
5(10)+3S=131
:
3S=81
:
b)number of small bottles sold
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