SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x) = -2x^2+2x+1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x) = -2x^2+2x+1      Log On


   

Question 182769: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function f(x) = -2x^2+2x+1
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = -2x^2+2x+1
:
f%28x%29=-2%28x%5E2-2x%29%2B1
:
f%28x%29=-2%28x%5E2-x%2B%281%2F4%29%29%2B1%2B%281%2F2%29
:
f%28x%29=-2%28x-%281%2F2%29%29%5E2%2B%283%2F2%29
:
vertex is at (1/2,3/2)
:
line if symmetry is at x=1/2
:
maximum is at y=3/2
:
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-2x%5E2%2B2x%2B1%29