SOLUTION: Method of Substitution 5. Find the point of intersection of each pair of lines. e) x-2y-2=0 3x+4y-16=0 Pleaseeeeee can you help me? thanksssssssss

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Question 181853: Method of Substitution
5. Find the point of intersection of each pair of lines.
e) x-2y-2=0
3x+4y-16=0
Pleaseeeeee can you help me? thanksssssssss
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
x-2y-2=0 rearrange to isolate x on one side and everything else on the other. So Add 2y+2 to each side to get
x+=+2y+%2B+2
Now use this value for x and substitute it into the other equation
3x%2B4y-16=0
3%2A%282y%2B2%29+%2B+4y+-16+=+0
6y+%2B6+%2B+4y+-16+=+0
10y+-+10+=+0
10y+=+10
y+=+1
Now use this value of y and solve for x
x+=+2y+%2B+2
x+=+2%2A1+%2B+2
x+=+2%2B2
x+=+4
You can check your answer by verifying the point (4,1) is a solution to both equations.
Does x-2y-2=0 for (4,1)
4+-%282%2A1%29+-+2+=+0
0+=+0 which is true. So that works
Does 3x%2B4y-16=0 for (4,1)???
3%2A4+%2B+4%2A1+-+16+=0
12+%2B+4+-16+=+0
0+=+0 which is true.
the point where those two lines intersect is (4,1)