Question 180766: Linear Systems Problem Solving
3. One equation of a system is 2x-y=5. Write a second equation so that the system has
a) no solution
b) infinitely many solutions
c) one solution, (3, 1). pleaseeeee
Thanks a lotttt
Answer by user_dude2008(1862) (Show Source):
You can put this solution on YOUR website! a)
Just change the 5 to something else. So other equation is 2x-y=7
b)
Multiply all numbers by 2. So equation is 4x-2y=10
c)
Make up 2 numbers for left side. So I chose 4 and 5. Left side is now 4x+5y
Plug in (3,1) -----> 4(3)+5(1)=12+5=17
Equation is 4x+5y=17
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