SOLUTION: I need help please show me an example of a complex roots equation. Thanks

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Question 180687: I need help please show me an example of a complex roots equation. Thanks
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 1 = 0 has two complex roots.
(x+i)(x-i) = 0
x = -i or x = +i
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Cheers,
Stan H.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose the roots are i+%2B+1 and i+-+1, then
the equation can be factored into
%28x+-+%281+%2B+i%29%29 and %28x+-+%281+-+i%29%29, so
%28x+-+%281+%2B+i%29%29%28x+-+%281+-+i%29%29+=+0
Note that if you replace x by either 1+%2B+i or 1+-+i,
Then the equation is solved
Now multiplying the factors:
x%5E2+-%281+%2B+i%29x+-+%281+-+i%29x+%2B+%281+%2B+i%29%281+-+i%29+=+0
x%5E2+-+x+-+ix+-+x+%2B+ix+%2B+1+%2B+i+-+i+-+i%5E2+=+0
(note that i%5E2+=+-1 and -i%5E2+=+%2B1)
x%5E2+-+x+-+ix+-+x+%2B+ix+%2B+1+%2B+i+-+i+-+i%5E2+=+x%5E2+-+2x+%2B+2
x%5E2+-+2x+%2B+2+=+0 is the equation to find roots
y+=+x%5E2+-+2x+%2B+2 is the complete complex roots equation
There are 2 complex roots to this equation,
1+%2B+i and 1+-+i
Graphing it, you can see it doesn't intersect the x-axis, where
real roots would be:
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+-+2x+%2B+2%29+