SOLUTION: 13) Solve by using quadratic formula x2 – 6x + 10 = 0 14) Solve by using quadratic formula x2 – 4x + 29 = 0
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-> SOLUTION: 13) Solve by using quadratic formula x2 – 6x + 10 = 0 14) Solve by using quadratic formula x2 – 4x + 29 = 0
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Question 180589
:
13) Solve by using quadratic formula x2 – 6x + 10 = 0
14) Solve by using quadratic formula x2 – 4x + 29 = 0
Answer by
vleith(2983)
(
Show Source
):
You can
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Do the work, then use this URl to check your answers --> http://www.algebra.com/algebra/homework/quadratic/quadratic.solver
Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
The discriminant -4 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about
imaginary numbers
, read on.
In the field of imaginary numbers, the square root of -4 is + or -
.
The solution is
Here's your graph:
Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
The discriminant -100 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about
imaginary numbers
, read on.
In the field of imaginary numbers, the square root of -100 is + or -
.
The solution is
Here's your graph: