SOLUTION: The directions say: Solve each equation by graphing. If integral roots cannot be found, estimate the roots by stating the consecutive integers between which the roots lie. The

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The directions say: Solve each equation by graphing. If integral roots cannot be found, estimate the roots by stating the consecutive integers between which the roots lie. The      Log On


   

Question 180302This question is from textbook Algebra I
: The directions say: Solve each equation by graphing. If integral roots cannot be found, estimate the roots by stating the consecutive integers between which the roots lie.
The problem is written as
x%5E2%2B6x=-7 This question is from textbook Algebra I

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+6x+=+-7
x%5E2+%2B+6x+%2B+%286%2F2%29%5E2+=+-7+%2B+%286%2F2%29%5E2
%28x+%2B+3%29%5E2+=+-7+%2B+9
%28x+%2B+3%29%5E2+=+2
Take the square root of both sides
x+%2B+3+=+sqrt%282%29
x+=+sqrt%282%29+-+3
x+=+1.414+-+3
x+=+-1.586
and
x+%2B+3+=+-%28sqrt%282%29%29
x+=+-%28sqrt%282%29%29+-+3
x+=+-4.414
graphing:
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+%2B+6x+%2B+7%29+
One root lies between -1 and -2
The other root lies between -4 and -5