SOLUTION: I am having some trouble with quadratic formulas, can you help me please? Here is the problem: 4x^2-x+1=0 This is what I have so far: A=4 B=-1 C=1 X= 1+/-(radical sign)(-1)^2-4(4(1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I am having some trouble with quadratic formulas, can you help me please? Here is the problem: 4x^2-x+1=0 This is what I have so far: A=4 B=-1 C=1 X= 1+/-(radical sign)(-1)^2-4(4(1      Log On


   

Question 180002This question is from textbook
: I am having some trouble with quadratic formulas, can you help me please? Here is the problem: 4x^2-x+1=0 This is what I have so far: A=4 B=-1 C=1 X= 1+/-(radical sign)(-1)^2-4(4(1) (All over) 2(4) x=1+/-(radical sign)1-16 (all over) 8 x=1+/-(radical sign) -15 (all over) 8 x=1+/-(radical sign) -1(times)15 (all over) 8 x=1+/-i(racidal sign)15 (all over) 8 and that is as far as I got, Please help me! Thanks a ton,
Heather This question is from textbook

Found 3 solutions by ptaylor, josmiceli, solver91311:
Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2-x+1=0
LOOKS LIKE YOU PRETTY WELL HAVE THE PROBLEM SOLVED
Using the quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%281+%2B-+sqrt%28+1-16%29%29%2F%288%29+ =
x+=+%281+%2B-+sqrt%28-15%29%29%2F%288%29+ =
x+=+%281+%2B-+%28i%29sqrt%2815%29%29%2F%288%29+
----And that's about as far as you can go!
Good work!!!!!!!!!-----ptaylor

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let's see if your answer checks:
x+=+%281+%2B-sqrt%2815%29i%29%2F8
I'll plug 1 of these 2 answers back into the equation
4x%5E2+-+x+%2B+1+=+0
4%2A%28%281+%2B+sqrt%2815%29i%29%2F8%29%5E2+-+%281+%2B+sqrt%2815%29i%29%2F8+%2B+1+=+0
4%2A%281+%2B+2%2Asqrt%2815%29i+%2B+15%2Ai%5E2%29%2F64+-+1%2F8+-+sqrt%2815%29i%2F8+%2B+1+=+0
1%2F16+%2B+%28sqrt%2815%29i%29%2F8+-+15%2F16+-+1%2F8+-+sqrt%2815%29i%2F8+%2B+1+=+0
multiply both sides by 16
1+%2B+2%2A%28sqrt%2815%29i%29+-+15+-+2+-+2%2A%28sqrt%2815%29i%29+%2B+16+=+0
1+-+15+-+2+%2B+16+=+0
17+-+17+=+0
The other root should check out, too. I'll let you do it.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

And the place you arrived is a very fine place to be indeed in view of the fact that you have simplified the expression as far as possible and



are the exact roots of the given equation. Some purists might expect this to be expressed in complex number form, making your answer:



But if someone at this stage of your mathematics education were to insist upon it, you might be well justified to reply with an eye-roll and a "whatever." The only other thing I can think of is to separate the plus/minus and show the two conjugates as separate entities if your instructor insists, but again, it hardly makes a difference IMHO.

Anything else you might do to this would only result in a numerical approximation of the answer. Good job, Heather.

John