SOLUTION: In a Quadratic Equation of (z+5)(z+1)=10z how to you work it.

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Question 1782: In a Quadratic Equation of (z+5)(z+1)=10z how to you work it.
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
to solve any quadratic, you are trying to find where it equals zero, that is where it crosses the x-axis of a graph. Those points that it does cross the x-axis at are called the root(s) of the equation.
So, first thing is to get everything on one side, so that it equals zero...then we try to find the answers.
First, multiply out the brackets and collect terms together, all on one side, like so...
z%5E2+%2B+z+%2B+5z+%2B+5+=+10z
z%5E2+%2B+6z+%2B+5+=+10z
z%5E2+-+4z+%2B+5+=+0
Now we need to solve this. The 2 main methods are to factorise (meaning find 2 things multiplied together) or use the quadratic formula.
Factorise should always be your first route...
However, I have looked at this, and there are no solutions (at a low level of algebra at least), so have you written the question correctly?
If you have, then the answer is either: no solution or you use "Complex Numbers", which is an advanced maths comcept.
Hope this helps
cheers
Jon.