Question 177456: This is one question with different parts, please help. Thank you
Find the vertex, line of symmetry, the maximum or minimum value of the quadratic function
f(x)=-2x^2+2x+3
What is the x-coordinate of the vertex?
What is the y-coordinate of the vertex?
What is the equation of the line of symmetry?
The max/min of f(x) is?
The value, f(1/2)=7/2 is a maximum or a minimum?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the vertex, line of symmetry, the maximum or minimum value of the quadratic function
f(x)=-2x^2+2x+3
Complete the square to see the vertex form of the quadratic:
-2x^2 + 2x + ? = y - 3 + ?
-2(x^2 -x + (1/4)) = y - 3 - 2(1/4)
-2(x-(1/2))^2 = y - 3.5
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What is the x-coordinate of the vertex?
x = 1/2
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What is the y-coordinate of the vertex?
y = 3.5
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What is the equation of the line of symmetry?
x = 1/2
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f(x)=-2x^2+2x+3
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The max/min of f(x) is?
Min or max occurs when x = -b/2a = -2/(2*-2) = 1/2
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The value, f(1/2)=7/2 is a maximum or a minimum?
It is a max because the coefficient of x^2 is negative.
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Cheers,
Stan H.
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