SOLUTION: Hi how would you solve this: (x+8)^2-54=0 Thanks.

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Question 177301: Hi how would you solve this:
(x+8)^2-54=0
Thanks.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B8%29%5E2-54=0 Start with the given equation.


%28x%2B8%29%5E2=54 Add 54 to both sides.


x%2B8=0%2B-sqrt%2854%29 Take the square root of both sides.


x%2B8=sqrt%2854%29 or x%2B8=-sqrt%2854%29 Break up the "plus/minus"


x%2B8=3%2Asqrt%286%29 or x%2B8=-3%2Asqrt%286%29 Simplify the square root.


x=-8%2B3%2Asqrt%286%29 or x=-8-3%2Asqrt%286%29 Subtract 8 from both sides.


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Answer:

So the solutions are x=-8%2B3%2Asqrt%286%29 or x=-8-3%2Asqrt%286%29