Question 176901: Please help. Find the vertex, line of symmetry, minimum and maximum value for the quadratic equation. I can do it all after finding the vertex, but I am unsure of how to find it.
f(x)= 4-x^2
Thank you
Found 2 solutions by stanbon, Mathtut:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Please help. Find the vertex, line of symmetry, minimum and maximum value for the quadratic equation. I can do it all after finding the vertex, but I am unsure of how to find it.
f(x)= 4-x^2
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One Way to find vertex:
Put equation in standard form:
x^2 = -y+4
(x-0)^2 = -(y-4)
Vertex: (0,4)
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Another way to find Vertex:
x= -b/2a = -0/(2*-1) = 0
y = f(0) = 4
Vertex: (0,4)
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Cheers,
Stan H.
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! we know this parabola will open downward as the a is negative. so this will have a maximum
:y=a(x-h)+k.....(h,k) is the vertex
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axis of symmetry is x=h
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max min value is y=k
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vertex is at (0,4)
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line of symmetry is x=0. line of symmetry is nothing more than the line that splits the parabola in half
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max is y=4
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