SOLUTION: Hello, I need some help with this problem: Find the x intercepts of the quadratic equaiton {{{2x^2+3x+4=0}}} Thank you in advance.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hello, I need some help with this problem: Find the x intercepts of the quadratic equaiton {{{2x^2+3x+4=0}}} Thank you in advance.      Log On


   

Question 175608: Hello, I need some help with this problem:
Find the x intercepts of the quadratic equaiton
2x%5E2%2B3x%2B4=0
Thank you in advance.
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
There are different ways to approach this problem, but probably the most common is the quadratic formula. Starting with ax%5E2%2Bbx%2Bc=0 we have that
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
In this problem, a=2, b=3, and c=4, so we get
x=%28-3%2B-sqrt%283%5E2-4%282%29%284%29%29%29%2F%282%282%29%29
So
x=%28-3%2B-sqrt%28-23%29%29%2F4
Note that sqrt%28-23%29 does not yield a real number. This means that there are no x-intercepts. This can be validated from the graph (you can see that the graph never crosses the x-axis):
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2x%5E2%2B3x%2B4%29