SOLUTION: How do I find the discriminant of this equation? x^2+11x+121=x+96

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: How do I find the discriminant of this equation? x^2+11x+121=x+96      Log On


   

Question 174866: How do I find the discriminant of this equation? x^2+11x+121=x+96
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B11x%2B121=x%2B96 Start with the given equation.


x%5E2%2B11x%2B121-1x-96=0 Subtract x from both sides. Subtract 96 from both sides.


x%5E2%2B10x%2B25=0 Combine like terms.

------------------------------------------

Now let's find the discriminant of x%5E2%2B10x%2B25:


From x%5E2%2B10x%2B25 we can see that a=1, b=10, and c=25


D=b%5E2-4ac Start with the discriminant formula.


D=%2810%29%5E2-4%281%29%2825%29 Plug in a=1, b=10, and c=25


D=100-4%281%29%2825%29 Square 10 to get 100


D=100-100 Multiply 4%281%29%2825%29 to get %284%29%2825%29=100


D=0 Subtract 100 from 100 to get 0


So the discriminant is 0.


Note: Since the discriminant is equal to zero, this means that there is one real solution.