SOLUTION: how do i convert this into a form i can solve as a quadratic equation? 9(p-300)^2= 1.02^2 *p(400-p)

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Question 173108: how do i convert this into a form i can solve as a quadratic equation?
9(p-300)^2= 1.02^2 *p(400-p)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
how do i convert this into a form i can solve as a quadratic equation?
9(p-300)^2= 1.02^2 *p(400-p)
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expand all the terms.
9(p-300)^2= 1.02^2 *p(400-p)
9(p^2 - 600p + 90000) = 1.0404*(400p - p^2)
9p^2 - 5400 p + 810000 = 416.16p - 1.0404p^2
p^2 - 600p + 90000 = 46.24p - 0.1156p^2
Collect terms
1.1156p^2 - 646.24p + 90000 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1.1156x%5E2%2B-646.24x%2B90000+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-646.24%29%5E2-4%2A1.1156%2A90000=16010.1376.

Discriminant d=16010.1376 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--646.24%2B-sqrt%28+16010.1376+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-646.24%29%2Bsqrt%28+16010.1376+%29%29%2F2%5C1.1156+=+346.34778255817
x%5B2%5D+=+%28-%28-646.24%29-sqrt%28+16010.1376+%29%29%2F2%5C1.1156+=+232.92794350852

Quadratic expression 1.1156x%5E2%2B-646.24x%2B90000 can be factored:
1.1156x%5E2%2B-646.24x%2B90000+=+%28x-346.34778255817%29%2A%28x-232.92794350852%29
Again, the answer is: 346.34778255817, 232.92794350852. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1.1156%2Ax%5E2%2B-646.24%2Ax%2B90000+%29