SOLUTION: use the given values to find an equation of the form f(x)= ax^2 + bx + c 1. f(0)= 5, f(1)=10, f(2)= 19 Please explain step by step so I understand! I would really appreci

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: use the given values to find an equation of the form f(x)= ax^2 + bx + c 1. f(0)= 5, f(1)=10, f(2)= 19 Please explain step by step so I understand! I would really appreci      Log On


   



Question 172691: use the given values to find an equation of the form f(x)= ax^2 + bx + c
1. f(0)= 5, f(1)=10, f(2)= 19
Please explain step by step so I understand!
I would really appreciate any help!
Thank you very much

Found 2 solutions by checkley77, solver91311:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)= ax^2 + bx + c
f(0)= 5
f(0)=a*0^2+b*0+c=5
f(0)=0+0+c=5
f(0)c=5 ans.
f(1)=10
f(1)=a*1^2+b*1+5
f(1)a+b+5=10 multiply this equation by -2 & add.
f(2)= 19
f(2)=a*2^2+b*2+5
f(2)4a+2b+5=19
------------------------------
-2a-2b-10=-20
4a+2b+5=19 add.
-----------------
2a-5=-1
2a=-1+5
2a=4
a=4/2
a=2 ans.
2+b+5=10
b=10-5-2
b=3 ans.
Proof:
4*2+2*3+5=19
8+6+5=19
19=19

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
If f is a function, then f%28a%29 is the value of the function evaluated at a. You are given the values of the function evaluated at 0, 1, and 2. So:
(1) f%280%29=5 means that a%280%29%5E2%2Bb%280%29%2Bc=5, simplified c=5

(2) f%281%29=10 means that a%281%29%5E2%2Bb%281%29%2Bc=10, simplified a%2Bb%2Bc=10

(3) f%282%29=19 means that a%282%29%5E2%2Bb%282%29%2Bc=19, simplified 4a%2B2b%2Bc=19

Since from (1) we have c=5, that can be substituted into (2) and (3), thus:

(4) a%2Bb%2B5=10 yielding a%2Bb=5 and,

(5) 4a%2B2b%2B5=19 yielding 4a%2B2b=14 yielding 2a%2Bb=7

Multiply (5) by -1:

(6) -2a-b=-7

Add (6) to (4) term-by-term:

(7) -a%2B0b=-2 or a=2

Substitute a=2 into (4):

(8) 2%2Bb=5 or b=3

Now you can say that f%28x%29=2x%5E2%2B3x%2B5 by substituting the values determined for a, b, and c when the system of linear equations was solved.

Check:
f%280%29=2%280%29%5E2%2B3%280%29%2B5=0%2B0%2B5=5 Check

f%281%29=2%281%29%5E2%2B3%281%29%2B5=2%2B3%2B5=10 Check

f%282%29=2%282%29%5E2%2B3%282%29%2B5=8%2B6%2B5=19 Check