SOLUTION: help! Find zeros for the function: g(x) = 6 - x^2 -5x h(x) = x^2 + 6x + 12
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-> SOLUTION: help! Find zeros for the function: g(x) = 6 - x^2 -5x h(x) = x^2 + 6x + 12
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Question 172630
:
help!
Find zeros for the function:
g(x) = 6 - x^2 -5x
h(x) = x^2 + 6x + 12
Answer by
KnightOwlTutor(293)
(
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):
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Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
Discriminant d=1 is greater than zero. That means that there are two solutions:
.
Quadratic expression
can be factored:
Again, the answer is: -3, -2. Here's your graph:
Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
The discriminant -12 is less than zero. That means that there are no solutions among real numbers.
If you are a student of advanced school algebra and are aware about
imaginary numbers
, read on.
In the field of imaginary numbers, the square root of -12 is + or -
.
The solution is
Here's your graph: