SOLUTION: I can't seem to finish this problem :( Can someone plese help me so I can see what I am doing wrong?? Solve for x: (4/x^2-1)=(2/x-1)-(3/x+1)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I can't seem to finish this problem :( Can someone plese help me so I can see what I am doing wrong?? Solve for x: (4/x^2-1)=(2/x-1)-(3/x+1)      Log On


   

Question 169930: I can't seem to finish this problem :( Can someone plese help me so I can see what I am doing wrong??
Solve for x: (4/x^2-1)=(2/x-1)-(3/x+1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x: (4/x^2-1)=(2/x-1)-(3/x+1)
----------------------
(4/x^2-1)=(2/x-1)-(3/x+1) Is it (2/x)+1, or 2/(x+1)?
I'll assume the latter.
4/(x^2-1) = 2/(x-1) - 3/(x+1)
4%2F%28%28x-1%29%2A%28x%2B1%29%29+=+2%2F%28x-1%29+-+3%2F%28x%2B1%29
Multiply by (x-1)*(x+1)
4 = 2(x+1) - 3(x-1)
4 = 2x+2 - 3x+3
4 = 5x +5
5x = -1
x = -1/5