SOLUTION: 3x^3+x^2-3x-1=0 (The ^3 and ^2 and exponents) I have tried to factor and pull out the x but I am getting confused with the two different power. I got x=-1, x=-1/3 and x=1 b

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 3x^3+x^2-3x-1=0 (The ^3 and ^2 and exponents) I have tried to factor and pull out the x but I am getting confused with the two different power. I got x=-1, x=-1/3 and x=1 b      Log On


   

Question 168539: 3x^3+x^2-3x-1=0 (The ^3 and ^2 and exponents)

I have tried to factor and pull out the x but I am getting confused with the two different power. I got x=-1, x=-1/3 and x=1 but i dont think i need three answers
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3x^3+x^2-3x-1=0
x^2(x+1) -3(x+1) = 0
(x+1)(x^2-3) = 0
x = -1 or x=sqrt(3) or x=-sqrt(3)
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Cheers,
Stan H.