SOLUTION: I asked before : Nathan made a triangular pennant for the band booster club. The are of the pennant is 80 square feet. The base of the pennant is 12 feet shorter than the height.

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Question 162177: I asked before :
Nathan made a triangular pennant for the band booster club. The are of the pennant is 80 square feet. The base of the pennant is 12 feet shorter than the height.
a) what are the lengths of the base and height of the pennant?
b)what are the dimensions of the pennant if the base is only 6 feet shorter that the height?
(I really do not understand this problem at all; do we use 1/2(b)(h)
please help soon!
and Checkly77 kindly answered my question.
AREA OF A TRIANGLE=BH/2
(H-12)H/2=80
(H^2-12H)/2=80
H^2-12H=2*80
H^2-12H=160
H^2-12H-160=0
(H-20)(H+8)=0
H-20=0
H=20 IS THE HEIGHT.
20-12=8 FOR THE BASE.
PROOF:
8*20/2=80
160/2=80
80=80
but I am not sure of the b part I don't know if the dimensions are the same or what? could somebody just please help me with the b part.
thank you very much
Found 2 solutions by vleith, checkley77:
Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website!

1)You got that one correct
2)Dimensions are different, but the area is the same

h = 16
so b = 10

Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
b)what are the dimensions of the pennant if the base is only 6 feet shorter that the height?
B=H-6
80=BH/2
80=(H-6)H/2
80=(H^2-6H)/2
H^2-6H=160
H^2-6H-160=0
(H-16)(H+10)=0
H-16=0
H=16 ANSWER.
B=16-6
B=10 ANSWER.
PROOF:
80=10*16/2
80*2=160
160=160