SOLUTION: pls.help me solve the following quadratic equation by factoring: {{{2x^2-3x+1=0}}} {{{4x^2+9x=9}}} {{{2y^2+y=-11y}}} {{{y^2-7-44=0}}} {{{6x^2+11x-1=0}}} pls. submit your

Multiply the  in front by the ,
getting .  So we write down



as the only way to find two factors of .

Next look at the sign of the last term  
on the left.  It is  so beside 
we write the sum , and what it equals, :.  

   

We observe that the absolute
value of the coefficient of the middle term on the left of
 is  so we replace the  by
, so

   becomes



Now place the  on the left of the  as



Us the distributive property to multiply out 
as . So now we have:



Out of the first two terms on the left ONLY, ,
we can factor out , getting  

Out of the last two terms on the left ONLY, ,
we can factor out , getting .

[Notice when the first of the last two terms begins
with a "-" sign, always take out a "-" term, which
will invariably change the sign of the second term.]

So we have



Now we take out the parentheses  as a
common factor and leave the  and the 
to put inside parentheses, like this:



Noqw we use the zero-factor principle where we 
set each factor = 0:


  
So the solution set is 

That's just the first one.  If I have time I will come back
and finish the rest.  So check this site later, for I will
probably do some more.

Edwin