SOLUTION: you have thrown a baseball straight upward from a height of about 6 feet. A friend has used a stop watch to record the time the ball is in hte air. If it takes approximately 6.5
Question 154065This question is from textbook calculus 1 with precalulus
: you have thrown a baseball straight upward from a height of about 6 feet. A friend has used a stop watch to record the time the ball is in hte air. If it takes approximately 6.5 seconds before the ball strikes the ground, explain how you can find the ball's initial velocity. This question is from textbook calculus 1 with precalulus
You can put this solution on YOUR website! you have thrown a baseball straight upward from a height of about 6 feet. A friend has used a stop watch to record the time the ball is in the air. If it takes approximately 6.5 seconds before the ball strikes the ground, explain how you can find the ball's initial velocity.
;
Using the equation -16t^2 + vt + c = h
Where:
h = height of the ball at t sec
t = time in seconds
v = velocity (upward)
-16t^2 = gravity (downward)
c = initial height
:
In this problem t = 6.5 sec. c = 6 ft; h = 0 (ground)
:
-16(6.5^2) + 6.5v + 6 = 0
:
-16(42.25) + 6.5v + 6 = 0
:
-676 + 6.5v + 6 = 0
:
6.5v - 670 = 0
v =
v = 103.1 ft/sec is the velocity
