SOLUTION: Find three consecutive positive even intergers such that the product of the first and third is 60

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Question 149428: Find three consecutive positive even intergers such that the product of the first and third is 60
Answer by Fombitz(32388) About Me  (Show Source):
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Name three consecutive positive even integers, A, B, and C.
A=2N 2N makes the integer even
B=2N%2B2 Next even integer after 2N
C=2N%2B4 Next even integer after 2N+2
N%3E0 This makes the integers positive
A%2AC=60 The product of first and third integer.
2N%282N%2B4%29=60
4N%5E2%2B8N-60=0
N%5E2%2B2N-15=0
%28N%2B5%29%28N-3%29=0
N+5=0
N=-5, not allowed since N>0, from above.
.
.
.
N-3=0
N=3
A=2N=6
B=2N%2B2=8
C=2N%2B4=10
The three integers are then 6, 8, and 10.