SOLUTION: I cannot understand how to do these type of questions at all...Can you please help me and thanks:) Page 575 Number 2 I have to write in standard form and determine the values

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Question 146360This question is from textbook Beginning Algebra
: I cannot understand how to do these type of questions at all...Can you please help me and thanks:)
Page 575
Number 2
I have to write in standard form and determine the values of a,b, and c....
x^2 + 6x - 5 = 0
This question is from textbook Beginning Algebra

Answer by orca(409) About Me  (Show Source):
You can put this solution on YOUR website!
Rewrite it in standard form:
x^2 + 6x + (-5) = 0
So
a = 1
b = 6
c = -5
Substituting the values of a, b and c into the quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
we have
x+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A%28-5%29+%29%29%2F%282%2A1%29+
x+=+%28-6+%2B-+sqrt%28+56+%29%29%2F%282%29+
x+=+%28-6+%2B-+sqrt%28+4%2A14+%29%29%2F%282%29+
x+=+%28-6+%2B-+2sqrt%28+14+%29%29%2F%282%29+
x+=+-3+%2B-+sqrt%28+14+%29