SOLUTION: 2x^2+5x+3=0

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Question 1449: 2x^2+5x+3=0
Answer by jennyxnguyen(2) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 + 5x +3 = 0
divide everything by 2 to isolate the x^2.
x%5E2%2B5%2F2x%2B3%2F2=0
then use the additive inverse to subtract 3/2. resulting in ...
x%5E2%2B5%2F2x=-3%2F2
then take half of the X coeffecient (not the x squared)
5%2F2 >>>>> 5%2F2/2 >>> 5%2F4. <<< square this value. 25%2F26
then add this value (25%2F16) to both sides
x%5E2%2B5%2F2x%2B25%2F16=-3%2F2%2B25%2F16 >> x%5E2%2B5%2F2x%2B25%2F16=1%2F16
the factor out the first part of the equation before the equal sign.
%28x%2B5%2F4%29%28x%2B5%2F4%29=1%2F16
now take the square root of both sides.
sqrt%28%28x%2B5%2F4%29%28x%2B5%2F4%29%29=sqrt%281%2F16%29 equals
x+5/4 = +- squareroot of 1 over 4 (i`m sorry for not putting it in a formula, but it wouldn't let me)
then to isolate x, you subtract 5/4 from both sides. resulting in
x=-5%2F4%2B-sqrt%281%29%2F4