SOLUTION: One of my biggest problems in algebra is figuring how to turn a word problem into a solution so that i can solve it. For instance, A rectangular parking lot is 50 ft longer than it

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Question 144734: One of my biggest problems in algebra is figuring how to turn a word problem into a solution so that i can solve it. For instance, A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally.
Found 2 solutions by crystel, jim_thompson5910:
Answer by crystel(1) (Show Source):
You can put this solution on YOUR website!
thi may include the arabic voltage based on a mimic compentancy.{xc=2-1 *100=250
simple arabic expressions may be concidered when writing algebraric statements such as:
5533 *2634643*166363 ghdf fsfcv vivid icity may cause tooo u8ch of one per gamond=[5-1-50=521 ]]] in other terms such as the basic forieng type

Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Let W=width, L=length

Since the "parking lot is 50 ft longer than it is wide", this means that

Start with Pythagoreans theorem

Plug in

Foil . Square 250 to get 62,500.

Subtract 62,500 from both sides

Combine like terms

Factor the left side (note: if you need help with factoring, check out this solver)

Now set each factor equal to zero:
or

or Now solve for W in each case

So our answer is
or

Discarding the negative width, the only answer is . So the width is 150 feet.

Go back to the first equation

Plug in

Add

So the width is 150 feet and the length is 200 feet