You can put this solution on YOUR website! Of course there is a solution, in fact there are two solutions -- there always are when you have a quadratic equation. The fundamental theorem of algebra tells us that for a polynomial equation of degree there are always solutions.
In this case, however, there are no REAL number solutions. That is because the discriminant, i.e. the expression under the radical in , is less than zero:
.
Hence, the two roots of the given equation are a conjugate pair of complex numbers of the form , where and are real number coefficients and is the imaginary number defined by
