Question 144442: On this problem, just like the other, i don't understand how you can have the solution equal to zero. It says that i need to use the discriminant to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. How do i determine the number and types of solutions. For this equations 2x2 - 10x + 25 = 0. Please help me someone.
Found 2 solutions by stanbon, nabla:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! use the discriminant to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. How do i determine the number and types of solutions. For this equations 2x2 - 10x + 25 = 0.
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You have a quadratic with a=2 ; b = -10 ; c = 25
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The discriminant is b^2-4ac:
(-10)^2 - 4*2*25 = 100-200 = -100
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Since the discriminant is negative the equation has two
complex solutions that are unequal.
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Cheers,
Stan H.
Answer by nabla(475) (Show Source):
You can put this solution on YOUR website! The discriminant is b^2-4ac for equation ax^2+bx+c=0. For your problem that is 100-200=-100. Now, if we used this in the quadratic formula,  , we would get a negative square root, which by definition causes the equation to have no real roots. (The solutions will consist of two complex numbers because of the +/- and the discriminant not equaling 0.)
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