SOLUTION: x^2 -3x = -6x -1 Can somebody explain how to do these? I have a whole paper of them to solve and don't know where to start! Get all the terms on the left, and 0 on the right si

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: x^2 -3x = -6x -1 Can somebody explain how to do these? I have a whole paper of them to solve and don't know where to start! Get all the terms on the left, and 0 on the right si      Log On


   

Question 144284: x^2 -3x = -6x -1
Can somebody explain how to do these? I have a whole paper of them to solve and don't know where to start!
Get all the terms on the left, and 0 on the right side.
x%5E2-3x+=+-6x-1
x%5E2%2B3x%2B1+=+0 Add and subtract to make the right side 0.
Then use the quadratic equation to solve.
a = 1, b = 3, c = 1
x+=+%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F2a
This gives %28-3%2Bsqrt%285%29%29%2F2, and %28-3-sqrt%285%29%29%2F2
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