SOLUTION: Please help. Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h = -16t^2 + 64t. What is the maximum height reached by the bal

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Please help. Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h = -16t^2 + 64t. What is the maximum height reached by the bal      Log On


   

Question 144024: Please help.
Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h = -16t^2 + 64t. What is the maximum height reached by the ball?
Thanks
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h = -16t^2 + 64t. What is the maximum height reached by the ball?
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You have a quadratic with a = -16 and b = 64
The max occurs when t = -b/2a = -64/(2*-16) = 2 second
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The height at t = 2 sec is as follows:
h(2) = -16(2)^2 + 64(2) = 64 ft
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Cheers,
Stan H.