SOLUTION: For this formula find the (a)vertex; (b)axis of symmetry;(c)determine whether there is a maximum or minimum value and find that value; and (d) graph the function: g(x) = -2x^2 +

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: For this formula find the (a)vertex; (b)axis of symmetry;(c)determine whether there is a maximum or minimum value and find that value; and (d) graph the function: g(x) = -2x^2 +       Log On


   



Question 143484This question is from textbook College Algebra
: For this formula find the (a)vertex; (b)axis of symmetry;(c)determine whether there is a maximum or minimum value and find that value; and (d) graph the function:
g(x) = -2x^2 + 2x +1
I know the answer--its in my book, but I cannot seem to figure out how to get to that answer. please help!!!!
This question is from textbook College Algebra

Answer by nabla(475) About Me  (Show Source):
You can put this solution on YOUR website!
Vertex--> x= -b/2a for quadratic equation in form ax^2+bx+c=0.
Axis of symmetry--> in general the x value of the vertex.
Max/min--> Without the use of calculus, we can notice that this will be a parabola that opens DOWNWARD (leading term, a, is negative), thus the vertex has to be the maximum.
In order to graph, find the intercepts by setting g(x)=0, then find the y-intercept by setting x=0. You have essentially all the information, now, to produce this:

graph%28+300%2C+300%2C+-5%2C+5%2C+-30%2C+30%2C+-2x%5E2+%2B+2x+%2B1+%29
If you want me to go more in-depth send me an E-mail at enabla@gmail.com .